2/(x+2)=-x/(x^2+5x+6)

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Solution for 2/(x+2)=-x/(x^2+5x+6) equation: 



2/(x+2)=-x/(x^2+5x+6)

We move all terms to the left:

2/(x+2)-(-x/(x^2+5x+6))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x^2+5x+6))!=0

x∈R



We calculate fractions


(2x^2+10x)/((x+2)*(x^2+5x+6)))+(-(-x*(x+2))/((x+2)*(x^2+5x+6)))=0



We calculate terms in parentheses: -(-x*(x+2))/((x+2)*(x^2+5x+6))), so:

-x*(x+2))/((x+2)*(x^2+5x+6))

We multiply all the terms by the denominator


-x*(x+2))

We multiply parentheses

-x^2-2x^2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

-(-3x^2)



We get rid of parentheses

3x^2+(2x^2+10x)/((x+2)*(x^2+5x+6)))+(=0

We multiply all the terms by the denominator


3x^2*((x+2)*(x^2+5x+6)))+(+(2x^2+10x)=0

We get rid of parentheses

3x^2*((x+2)*(x^2+5x+6)))+(+2x^2+10x=0

We add all the numbers together, and all the variables

2x^2+3x^2*((x+2)*(x^2+5x+6)))+(+10x=0

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